Is cube root integer?

Question

This seems to be simple but I cannot find a way to do it. I need to show whether the cube root of an integer is integer or not. I used is_integer() float method

Answer 1

If your numbers aren't big, I would do:

def is_perfect_cube(number):
    return number in [x**3 for x in range(15)]

Of course, 15 could be replaced with something more appropriate.

If you do need to deal with big numbers, I would use the sympy library to get more accurate results.

from sympy import S, Rational

def is_perfect_cube(number):
    # change the number into a sympy object
    num = S(number)
    return (num**Rational(1,3)).is_Integer