copy cell style openpyxl

Question

I am trying to copy a sheet, default_sheet, into a new sheet new_sheet in the same workbook.

I did managed to create a new sheet and to cop

Answer 1

As of openpyxl 2.5.4, python 3.4: (subtle changes over the older version below)

new_sheet = workbook.create_sheet(sheetName)
default_sheet = workbook['default']

from copy import copy

for row in default_sheet.rows:
    for cell in row:
        new_cell = new_sheet.cell(row=cell.row, column=cell.col_idx,
                value= cell.value)
        if cell.has_style:
            new_cell.font = copy(cell.font)
            new_cell.border = copy(cell.border)
            new_cell.fill = copy(cell.fill)
            new_cell.number_format = copy(cell.number_format)
            new_cell.protection = copy(cell.protection)
            new_cell.alignment = copy(cell.alignment)

For openpyxl 2.1

new_sheet = workbook.create_sheet(sheetName)
default_sheet = workbook['default']

for row in default_sheet.rows:
    for cell in row:
        new_cell = new_sheet.cell(row=cell.row_idx,
                   col=cell.col_idx, value= cell.value)
        if cell.has_style:
            new_cell.font = cell.font
            new_cell.border = cell.border
            new_cell.fill = cell.fill
            new_cell.number_format = cell.number_format
            new_cell.protection = cell.protection
            new_cell.alignment = cell.alignment