Why must virtual base classes be constructed by the most derived class?

Question

The following code won\'t compile:

class A {
public:
    A(int) {}
};

class B: virtual public A {
public:
    B(): A(0) {}
};

// most derived class
class C         


        

Answer 1

Because it avoids this:

class A {
public:
    A(int) {}
};

class B0: virtual public A {
public:
    B0(): A(0) {}
};

class B1: virtual public A {
public:
    B1(): A(1) {}
};

class C: public B0, public B1 {
public:
    C() {} // How is A constructed? A(0) from B0 or A(1) from B1?
};