Is it possible to print a variable's type in standard C++?

Question

For example:

int a = 12;
cout << typeof(a) << endl;

Expected output:

int

Answer 1

#include 
#include 
using namespace std;
#define show_type_name(_t) \
    system(("echo " + string(typeid(_t).name()) + " | c++filt -t").c_str())

int main() {
    auto a = {"one", "two", "three"};
    cout << "Type of a: " << typeid(a).name() << endl;
    cout << "Real type of a:\n";
    show_type_name(a);
    for (auto s : a) {
        if (string(s) == "one") {
            cout << "Type of s: " << typeid(s).name() << endl;
            cout << "Real type of s:\n";
            show_type_name(s);
        }
        cout << s << endl;
    }

    int i = 5;
    cout << "Type of i: " << typeid(i).name() << endl;
    cout << "Real type of i:\n";
    show_type_name(i);
    return 0;
}

Output:

Type of a: St16initializer_listIPKcE
Real type of a:
std::initializer_list
Type of s: PKc
Real type of s:
char const*
one
two
three
Type of i: i
Real type of i:
int