How to modify the local namespace in python

Question

How can I modify the local namespace of a function in python? I know that locals() returns the local namespace of the function when called inside it, but I want to do somet

Answer 1

A function that's not executing doesn't have any locals; the local context is created when you run the function, and destroyed when it exits, so there's no "local namespace" to modify from outside the function.

You can do something like this, though:

def f():
    g = [1]
    def func():
        print g[0]
    return func, g

f, val = f()
f()
val[0] = 2
f()

This uses an array to simulate a reference.