Curry Function in Swift

Question

I want to make a function that return a curry function like below

func addTwoNumbers(a: Int)(b: Int) -> Int {
    return a + b
}

addTwoNumbers(4)(b: 6) /         


        

Answer 1

In case you want to quickly get the curry function for any number of parameters, it's possible to generate it as shown in this gist.

The code is in Swift 2.2 and generates code for Swift 2.2 (at the moment). It uses simple template-based approach (a possible alternative is constructing an AST followed by code-generation):

func genCurry(n: Int, indent: Indent = .fourSpaces, accessLevel: AccessLevel = .Default, verbose: Bool = false) -> String {

    // ...
    // The bulky park is skipped for clarity.

    return accessLevel.asPrefix + "func curry<\(genericParams)>(f: \(fSig)) -> \(curriedSig(n)) {\n"
        + indent.single + "return \(closure)\n"
        + "}\n"
}