Why does the compiler choose bool over string for implicit typecast of L“”?

Question

Having recently introduced an overload of a method the application started to fail. Finally tracking it down, the new method is being called where I did not expect it to be.

Answer 1

To simplify a bit, the following code

#include 
using namespace std;

void f(const string &s)
{  cout << "string version called" << endl;  }

void f(const bool &b)
{  cout << "bool version called" << endl;  }

int main()
{  f("Hello World");  }

prints "bool version called". Are you sure that your code fails only with the empty string?