C pointer notation compared to array notation: When passing to function

Question

My question is base on the following code:

int myfunct(int ary[], int arysize)   
int myfunct2(int *ary, int arysize)

 int main(void){
   int numary[10];
         


        

Answer 1

Those declarations are absolutely identical. To quote the standard:

A declaration of a parameter as "array of type" shall be adjusted to "qualified pointer to type"

C99 standard section 6.7.5.3 paragraph 7