About Pointers To Functions in function declarations

Question

#include
#include

int fun1()
{
    printf(\"I am fun1.\");
    return 0;
}

int fun2(int fun())
{
    fun();
    return 0;
}

int mai         


        

Answer 1

These two function definitions are equivalent in C:

 int fun2(int fun()) { ... }

and

 int fun2(int (*fun)()) { ... }

In the first function the parameter is adjusted to a function pointer. See C Standard paragraph:

(C99, 6.7.5.3p8) "A declaration of a parameter as ‘‘function returning type’’ shall be adjusted to ‘‘pointer to function returning type’’, as in 6.3.2.1."