About Pointers To Functions in function declarations

Question

#include
#include

int fun1()
{
    printf(\"I am fun1.\");
    return 0;
}

int fun2(int fun())
{
    fun();
    return 0;
}

int mai         


        

Answer 1

int fun2(int (*fun)()) and int fun2(int fun()) are exactly the same. When you declare a function argument from a function type, the compiler uses it as if it were a pointer to the same function type.