SQL method to replace repeating blanks with single blanks

Question

Is there a more elegant way of doing this. I want to replace repeating blanks with single blanks....

   declare @i int

    set @i=0
    while @i <= 20
           


        

Answer 1

create table blank(
field_blank char(100))

insert into blank values('yyy      yyyy')
insert into blank values('xxxx    xxxx')
insert into blank values ('xxx    xxx')
insert into blank values ('zzzzzz zzzzz')

update blank 
set field_blank = substring(field_blank,1,charindex(' ',field_blank)-1) + ' ' + ltrim(substring(field_blank,charindex(' ',field_blank) + 1,len(field_blank)))
where CHARINDEX (' ' , rtrim(field_blank)) > 1

select * from blank