SQL method to replace repeating blanks with single blanks

Question

Is there a more elegant way of doing this. I want to replace repeating blanks with single blanks....

   declare @i int

    set @i=0
    while @i <= 20
           


        

Answer 1

SELECT 'starting...' --sets @@rowcount
WHILE @@rowcount <> 0
    update myTable
    set myTextColumn = replace(myTextColumn, '  ', ' ')
    where myTextColumn like '%  %'