What Is a Curly-Brace Enclosed List If Not an intializer_list?

Question

I asked a question here: Lifetime Extension of a initializer_list return involving the non-functional code:

const auto foo = [](const auto& a, const auto         


        

Answer 1

I just thought that any time you did a curly-braced list you were creating an intializer_list.

That's not correct.

If that's not what's happening, what is a list in curly-braces?

struct Foo {int a; int b;};
Foo f = {10, 20};

The {10, 20} part is not an initializer_list. It's just a syntactic form to use a list of objects to create another object.

int a[] = {10, 20, 30};

Once again, it's a syntactic form to create an array.

The name for the syntactic form is braced-init-list.