Why does jQuery throw the error `fadeOut is not a function'?

Question

I am using jQuery and put this code in my javascript:

function HideMe(itemID) {
    var myDiv = \'item_\' + itemID;
    $(myDiv).fadeOut(\"slow\");
}
         


        

Answer 1

It looks like jquery is not correctly attached to the page.

Check your linking to jQuery.