Why does jQuery throw the error `fadeOut is not a function'?

Question

I am using jQuery and put this code in my javascript:

function HideMe(itemID) {
    var myDiv = \'item_\' + itemID;
    $(myDiv).fadeOut(\"slow\");
}
         


        

Answer 1

I had this error because I was using a slim version of jQuery. If you download the full version you should be okay.