Is there a way we can fill NAs in a zoo or xts object with limited number of NAs forward. In other words like fill
From playing around in data.table comes this hacky solution:
np1 <- 3 + 1
dt[,
x_filled := x[c(rep(1, min(np1, .N)), rep(NA, max(0, .N - np1)))],
by = cumsum(!is.na(x))]
# Or slightly simplified:
dt[,
x_filled := ifelse(rowid(x) < 4, x[1], x[NA]),
by = cumsum(!is.na(x))]
> dt
date x x_filled
1: 2019-02-14 1 1
2: 2019-02-15 NA 1
3: 2019-02-16 NA 1
4: 2019-02-17 NA 1
5: 2019-02-18 5 5
6: 2019-02-19 NA 5
7: 2019-02-20 NA 5
8: 2019-02-21 NA 5
9: 2019-02-22 NA NA
10: 2019-02-23 NA NA
11: 2019-02-24 11 11
12: 2019-02-25 12 12
13: 2019-02-26 NA 12
14: 2019-02-27 NA 12
15: 2019-02-28 NA 12
16: 2019-03-01 NA NA
17: 2019-03-02 NA NA
18: 2019-03-03 NA NA
19: 2019-03-04 19 19
20: 2019-03-05 20 20
We build on the fact that subsetting vectors with NA returns NA.
Data/Packages
library(zoo)
library(data.table)
x <- zoo(1:20, Sys.Date() + 1:20)
x[c(2:4, 6:10, 13:18)] <- NA
dt <- data.table(date = index(x), x = as.integer(x))