jQuery .inArray() always true?

Question

I\'m trying to use inarray but its always returning true? Any ideas? (all li\'s are showing)

$(\"#select-by-color-list li\").hide();

// get the select
var $         


        

Answer 1

ES6 to the rescue! Although not jQuery I thought worth answering for future readers...

ES6 introduces .includes() which works as you think $.inArray SHOULD work:

const myArray = ["a", "b", "c"];

console.log(myArray.includes("a")) /* true */
console.log(myArray.includes("d")) /* false */

Array.prototype.includes()