I have a dataframe that provides two integer columns with the Year and Week of the year:
import pandas as pd
import numpy as np
L1 = [43,44,51,2,5,12]
L2 = [
If you want to follow ISO Week Date
Weeks start with Monday. Each week's year is the Gregorian year in which the Thursday falls. The first week of the year, hence, always contains 4 January. ISO week year numbering therefore slightly deviates from the Gregorian for some days close to 1 January.
The following sample code, generates a sequence of 60 Dates, starting from 18Dec2016 Sun and adds the appropriate columns.
It adds:
Sample Code Below:
# Generate Some Dates
dft1 = pd.DataFrame(pd.date_range('2016-12-18', freq='D', periods=60))
dft1.columns = ['e_FullDate']
dft1['e_FullDateWeekDay'] = dft1.e_FullDate.dt.day_name().str.slice(0,3)
#Add a Week Start Date (Monday)
dft1['e_week_start'] = dft1['e_FullDate'] - pd.to_timedelta(dft1['e_FullDate'].dt.weekday,
unit='D')
dft1['e_week_startWeekDay'] = dft1.e_week_start.dt.day_name().str.slice(0,3)
#Add a Week Start Year
dft1['e_week_start_yr'] = dft1.e_week_start.dt.year
#Add a Week Number of Week Start Monday
dft1['e_week_no'] = dft1['e_week_start'].dt.week
#Add a Week Start generate from Week Number and Year
dft1['e_week_start_from_week_no'] = pd.to_datetime(dft1.e_week_no.astype(str)+
dft1.e_week_start_yr.astype(str).add('-1') ,format='%W%Y-%w')
dft1['e_week_start_from_week_noWeekDay'] = dft1.e_week_start_from_week_no.dt.day_name().str.slice(0,3)
with pd.option_context('display.max_rows', 999, 'display.max_columns', 0, 'display.max_colwidth', 9999):
display(dft1)