Find the last match with Java regex matcher

Question

I\'m trying to get the last result of a match without having to cycle through .find()

Here\'s my code:

String in = \"num 123 num 1 num 698 num 19238          


        

Answer 1

Java patterns are greedy by default, the following should do it.

    String in = "num 123 num 1 num 698 num 19238 num 2134";
    Pattern p = Pattern.compile( ".*num ([0-9]+).*$" );
    Matcher m = p.matcher( in );

    if ( m.matches() )
    {
        System.out.println( m.group( 1 ));
    }