Extract string with Python re.match

Question

import re
str=\"x8f8dL:s://www.qqq.zzz/iziv8ds8f8.dafidsao.dsfsi\"

str2=re.match(\"[a-zA-Z]*//([a-zA-Z]*)\",str)
print str2.group()

current result=> error
expec         


        

Answer 1

print re.sub(r"[.]","",re.search(r"(?<=//).*?(?=/)",str).group(0))

See this demo.