Handle an exception thrown in a generator

Question

I\'ve got a generator and a function that consumes it:

def read():
    while something():
        yield something_else()

def process():
    for item in read         


        

Answer 1

When a generator throws an exception, it exits. You can't continue consuming the items it generates.

Example:

>>> def f():
...     yield 1
...     raise Exception
...     yield 2
... 
>>> g = f()
>>> next(g)
1
>>> next(g)
Traceback (most recent call last):
  File "", line 1, in 
  File "", line 3, in f
Exception
>>> next(g)
Traceback (most recent call last):
  File "", line 1, in 
StopIteration

If you control the generator code, you can handle the exception inside the generator; if not, you should try to avoid an exception occurring.