Get a list of function names in a shell script [duplicate]

Answer 1

You call this function with no arguments and it spits out a "whitespace" separated list of function names only.

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function script.functions () {
    local fncs=`declare -F -p | cut -d " " -f 3`; # Get function list
    echo $fncs; # not quoted here to create shell "argument list" of funcs.
}

To load the functions into an array:

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declare MyVar=($(script.functions));

Of course, common sense dictates that any functions that haven't been sourced into the current file before this is called will not show up in the list.

To Make the list read-only and available for export to other scripts called by this script:

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declare -rx MyVar=($(script.functions));

To print the entire list as newline separated:

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printf "%s\n" "${MyVar[@]}";