Group and count values in an array

Question

I have an array with objects, like the following.

b = {
  \"issues\": [{
    \"fields\": {
      \"status\": {
        \"id\": \"200\",
        \"name\": \"B         


        

Answer 1

This is a perfect opportunity to use Array#reduce. That function will take a function that is applied to all elements of the array in order and can be used to accumulate a value. We can use it to accumulate an object with the various counts in it.

To make things easy, we track the counts in an object as simply {name: count, otherName: otherCount}. For every element, we check if we already have an entry for name. If not, create one with count 0. Otherwise, increment the count. After the reduce, we can map the array of keys, stored as keys of the object, to be in the format described in the question. See below.

var b = {
  "issues": [{
    "fields": {
      "status": {
        "id": "200",
        "name": "Backlog"
      }
    }
  }, {
    "fields": {
      "status": {
        "id": "202",
        "name": "close"
      }
    }
  }, {
    "fields": {
      "status": {
        "id": "201",
        "name": "close"
      }
    }
  }]
};

var counts = b.issues.reduce((p, c) => {
  var name = c.fields.status.name;
  if (!p.hasOwnProperty(name)) {
    p[name] = 0;
  }
  p[name]++;
  return p;
}, {});

console.log(counts);

var countsExtended = Object.keys(counts).map(k => {
  return {name: k, count: counts[k]}; });

console.log(countsExtended);

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Notes.

1. Array#reduce does not modify the original array.

2. You can easily modify the function passed to reduce to for example not distinguish between Backlog and backlog by changing

   var name = c.fields.status.name;
   

   into

   var name = c.fields.status.name.toLowerCase();
   

   for example. More advanced functionality can also easily be implemented.