Java Executors: how can I stop submitted tasks?

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抹茶落季
抹茶落季 2020-12-01 12:48

I have submitted a task using executors and I need it to stop after some time (e.g. 5 minutes). I have tried doing like this:

   for (Future fut : e         


        
5条回答
  •  不知归路
    2020-12-01 13:33

    Just because you call cancel() on Future doesn't mean that the task will stop automatically. You have to do some work within the task to make sure that it will stop:

    • Use cancel(true) so that an interrupt is sent to the task.
    • Handle InterruptedException. If a function in your task throws an InterruptedException, make sure you exit gracefully as soon as possible upon catching the exception.
    • Periodically check Thread.currentThread().isInterrupted() if the task does continuous computation.

    For example:

    class LongTask implements Callable {
        public Double call() {
            
             // Sleep for a while; handle InterruptedException appropriately
             try {
                 Thread.sleep(10000);
             } catch (InterruptedException ex) {
                 System.out.println("Exiting gracefully!");
                 return null;
             }
    
    
             // Compute for a while; check Thread.isInterrupted() periodically
             double sum = 0.0;
             for (long i = 0; i < 10000000; i++) {
                 sum += 10.0
                 if (Thread.currentThread().isInterrupted()) {
                     System.out.println("Exiting gracefully");
                     return null;
                 }
             }
    
             return sum;
        } 
    }
    

    Also, as other posts have mentioned: ConcurrentModificationException can be thrown even if using the thread-safe Vector class, because iterators you obtain from Vector are not thread-safe, and thus need to be synchronized. The enhanced for-loop uses iterators, so watch out:

    final Vector vector = new Vector();
    vector.add(1.0);
    vector.add(2.0);
    
    // Not thread safe!  If another thread modifies "vector" during the loop, then
    // a ConcurrentModificationException will be thrown.
    for (Double num : vector) {
        System.out.println(num);
    }
    
    // You can try this as a quick fix, but it might not be what you want:
    synchronized (vector) {    // "vector" must be final
        for (Double num : vector) {
            System.out.println(num);
        }
    }
    

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