How write a file using StreamWriter in Windows 8?

Question

I\'m having trouble when creating a StreamWriter object in windows-8, usually I just create an instance just passing a string as a parameter, but in Windows 8 I

Answer 1

You can create a common static method which you can use through out application like this

 private async Task ReadXml(StorageFile xmldata)
    {
        XmlSerializer xmlser = new XmlSerializer(typeof(List));
        T data;
        using (var strm = await xmldata.OpenStreamForReadAsync())
        {
            TextReader Reader = new StreamReader(strm);
            data = (T)xmlser.Deserialize(Reader);
        }
        return data;
    }

    private async Task writeXml(T Data, StorageFile file)
    {
        try
        {
            StringWriter sw = new StringWriter();
            XmlSerializer xmlser = new XmlSerializer(typeof(T));
            xmlser.Serialize(sw, Data);

            using (IRandomAccessStream fileStream = await file.OpenAsync(FileAccessMode.ReadWrite))
            {
                using (IOutputStream outputStream = fileStream.GetOutputStreamAt(0))
                {
                    using (DataWriter dataWriter = new DataWriter(outputStream))
                    {
                        dataWriter.WriteString(sw.ToString());
                        await dataWriter.StoreAsync();
                        dataWriter.DetachStream();
                    }

                    await outputStream.FlushAsync();
                }
            }


        }
        catch (Exception e)
        {
            throw new NotImplementedException(e.Message.ToString());

        }

    }

to write xml simply use

 StorageFile file = await ApplicationData.Current.LocalFolder.CreateFileAsync("data.xml",CreationCollisionOption.ReplaceExisting);
        await  writeXml(Data,file);

and to read xml use

  StorageFile file = await ApplicationData.Current.LocalFolder.GetFileAsync("data.xml");
      Data =  await  ReadXml>(file);