suppose I have this table
id | cash
1 200
2 301
3 101
4 700
and I want to return the first row in which the sum of all the pre
Not tested, but I think this will be close?
SELECT m1.id
FROM mytable m1
INNER JOIN mytable m2 ON m1.id < m2.id
GROUP BY m1.id
HAVING SUM(m1.cash) > 500
ORDER BY m1.id
LIMIT 1,2
The idea is to SUM up all the previous rows, get only the ones where the sum of the previous rows is > 500, then skip one and return the next one.