Override jQuery .val() function?

Question

Is there a way to easily override jQuery\'s val() function?

The reason I want to override it is that I want to add some processing each time a value is

Answer 1

I know it's an old subject but it's first in google search and the answer is not completely right...

For example if you try in the console $('#myinput').val() you should get the value of #myinput.

But if you do $('#myinput').val(undefined) you should set the value of #myinput!( With the current answer and the comments of it, you will not set the value of #myinput)

Here is an upgraded answer that use arguments.

(function ($) {
  var originalVal = $.fn.val;
  $.fn.val = function(value) {
    if (arguments.length >= 1) {
      // setter invoked, do processing
      return originalVal.call(this, value); 
    }
    //getter invoked do processing
    return originalVal.call(this);
  };
})(jQuery);

if you want to pass all the arguments you can also use apply

(function ($) {
  var originalVal = $.fn.val;
  $.fn.val = function(value) {
    if (arguments.length >= 1) {
      // setter invoked, do processing
    } else {
      //getter invoked do processing
    }
    return originalVal.apply(this, arguments);
  };
})(jQuery);

I hope it help!