Getting all types that implement an interface

Question

Using reflection, how can I get all types that implement an interface with C# 3.0/.NET 3.5 with the least code, and minimizing iterations?

This is what I want to re-

Answer 1

Other answers here use IsAssignableFrom. You can also use FindInterfaces from the System namespace, as described here.

Here's an example that checks all assemblies in the currently executing assembly's folder, looking for classes that implement a certain interface (avoiding LINQ for clarity).

static void Main() {
    const string qualifiedInterfaceName = "Interfaces.IMyInterface";
    var interfaceFilter = new TypeFilter(InterfaceFilter);
    var path = Path.GetDirectoryName(Assembly.GetExecutingAssembly().Location);
    var di = new DirectoryInfo(path);
    foreach (var file in di.GetFiles("*.dll")) {
        try {
            var nextAssembly = Assembly.ReflectionOnlyLoadFrom(file.FullName);
            foreach (var type in nextAssembly.GetTypes()) {
                var myInterfaces = type.FindInterfaces(interfaceFilter, qualifiedInterfaceName);
                if (myInterfaces.Length > 0) {
                    // This class implements the interface
                }
            }
        } catch (BadImageFormatException) {
            // Not a .net assembly  - ignore
        }
    }
}

public static bool InterfaceFilter(Type typeObj, Object criteriaObj) {
    return typeObj.ToString() == criteriaObj.ToString();
}

You can set up a list of interfaces if you want to match more than one.