Is it even possible to concatenate vectors in Rust? If so, is there an elegant way to do so? I have something like this:
let mut a = vec![1, 2, 3];
let b = v
Regarding the performance, slice::concat, append and extend are about the same. If you don't need the results immediately, making it a chained iterator is the fastest; if you need to collect(), it is the slowest:
#![feature(test)]
extern crate test;
use test::Bencher;
#[bench]
fn bench_concat___init__(b: &mut Bencher) {
b.iter(|| {
let mut x = vec![1i32; 100000];
let mut y = vec![2i32; 100000];
});
}
#[bench]
fn bench_concat_append(b: &mut Bencher) {
b.iter(|| {
let mut x = vec![1i32; 100000];
let mut y = vec![2i32; 100000];
x.append(&mut y)
});
}
#[bench]
fn bench_concat_extend(b: &mut Bencher) {
b.iter(|| {
let mut x = vec![1i32; 100000];
let mut y = vec![2i32; 100000];
x.extend(y)
});
}
#[bench]
fn bench_concat_concat(b: &mut Bencher) {
b.iter(|| {
let mut x = vec![1i32; 100000];
let mut y = vec![2i32; 100000];
[x, y].concat()
});
}
#[bench]
fn bench_concat_iter_chain(b: &mut Bencher) {
b.iter(|| {
let mut x = vec![1i32; 100000];
let mut y = vec![2i32; 100000];
x.into_iter().chain(y.into_iter())
});
}
#[bench]
fn bench_concat_iter_chain_collect(b: &mut Bencher) {
b.iter(|| {
let mut x = vec![1i32; 100000];
let mut y = vec![2i32; 100000];
x.into_iter().chain(y.into_iter()).collect::>()
});
}
running 6 tests
test bench_concat___init__ ... bench: 27,261 ns/iter (+/- 3,129)
test bench_concat_append ... bench: 52,820 ns/iter (+/- 9,243)
test bench_concat_concat ... bench: 53,566 ns/iter (+/- 5,748)
test bench_concat_extend ... bench: 53,920 ns/iter (+/- 7,329)
test bench_concat_iter_chain ... bench: 26,901 ns/iter (+/- 1,306)
test bench_concat_iter_chain_collect ... bench: 190,334 ns/iter (+/- 16,107)