How do I split a string by whitespace and ignoring leading and trailing whitespace into an array of words using a regular expression?

Question

I typically use the following code in JavaScript to split a string by whitespace.

\"The quick brown fox jumps over the lazy dog.\".split(/\\s+/);
// [\"The\"         


        

Answer 1

If you are more interested in the bits that are not whitespace, you can match the non-whitespace instead of splitting on whitespace.

"  The quick brown fox jumps over the lazy dog. ".match(/\S+/g);

Note that the following returns null:

"   ".match(/\S+/g)

So the best pattern to learn is:

str.match(/\S+/g) || []