Mirror image of a binary tree

Question

Suppose there is a tree:

             1
            / \\
           2   3
              / \\
             4   5

Then the mirror image will

Answer 1

void mirror(node *& root2,node * root)
{
    if(root==NULL)
    {
        root2=NULL;
    }
    else {
        root2=new node;
        root2->data=root->data;
        root2->left=NULL;
        root2->right=NULL;
        mirror(root2->left,root->right);
        mirror(root2->right,root->left);
    }
}