Changing array inside function in C

Question

I am learning C and confused why a array created in the main wont change inside the function, i am assuming the array passed is a pointer, and changing the pointer should\'v

Answer 1

            #include
            #include

            // Print on console the array of int
            void print(int *array,int length)
            {
                int i;
                for(i = 0 ; i < length ; i++)
                    printf("%d ", array[i]);
                printf("\n");
            }

            // Change the pointer of the array
            void change(int **array,int length)
            {
                int i;
                int *ar;
                ar = (int *)malloc(sizeof(int *) * length);
                for(i = 0 ; i < length ; i++)
                    ar[i] = 1;
                (*array) = ar;
            }

            int main(){
                int i, length = 10;
                int *array;
                array = (int *)malloc(sizeof(int *) * length);

                for (i = 0 ; i < length ; i++)
                    array[i] = i * 10;
                printf("Before:");
                print(array, length);
                change(&array, length);
                printf("After:");
                print(array, length);

                return 0;
            }