Changing array inside function in C

Question

I am learning C and confused why a array created in the main wont change inside the function, i am assuming the array passed is a pointer, and changing the pointer should\'v

Answer 1

To use pass by value:
Make the following change:
In function change(...), replace:

int i;for(i=0;i

To:

int i;for(i=0;i

EDIT:
But to use pass by reference:

//To change the contents of a variable via a function call
//the address of that variable has to be passed. So, if you
//want to change the contents of an array of int, i.e. int *array, you 
//need to pass its address, not the variable itself,  using the 
//address of operator, it would look like this &array (read _the address of
// pointer to int "array")
//This requires you to change the prototype of your function:
void change2(int **a, int len)
{
    int i;
    for(i=0;i

Then in main, make the following changes, and it will work as you purposed:

int main(){
    int i,length=10;
    int *array;

    array = calloc(length, sizeof(int));
    if(!array) return 0;
    //or malloc if preferred.  But note, in C, 
    //casting the output is not required on either.
    //array = malloc(length*sizeof(int));
    //if(!array) return 0;

    for(i=0;i