Is it possible to initialize std::vector over already allocated memory?

前端 未结 3 2043
伪装坚强ぢ
伪装坚强ぢ 2020-12-01 08:16

My question is fairly simple and I am quite surprised I can\'t find anything related. Probably it is easy or totally stupid (or I can\'t search).

As the title says,

3条回答
  •  情话喂你
    2020-12-01 08:41

    Like this.. Containers in the standard usually take an allocator. Using c++11's allocator traits, it is very easy to create an allocator as you don't have to have all the members in the allocator. However if using an older version of C++, you will need to implement each member and do the rebinding as well!

    For Pre-C++11, you can use the following:

    #include 
    #include 
    #include 
    
    template
    class PreAllocator
    {
        private:
            T* memory_ptr;
            std::size_t memory_size;
    
        public:
            typedef std::size_t size_type;
            typedef ptrdiff_t difference_type;
            typedef T* pointer;
            typedef const T* const_pointer;
            typedef T& reference;
            typedef const T& const_reference;
            typedef T value_type;
    
    
            PreAllocator(T* memory_ptr, std::size_t memory_size) throw() : memory_ptr(memory_ptr), memory_size(memory_size) {};
            PreAllocator (const PreAllocator& other) throw() : memory_ptr(other.memory_ptr), memory_size(other.memory_size) {};
    
            template
            PreAllocator (const PreAllocator& other) throw() : memory_ptr(other.memory_ptr), memory_size(other.memory_size) {};
    
            template
            PreAllocator& operator = (const PreAllocator& other) {return *this;}
            PreAllocator& operator = (const PreAllocator& other) {return *this;}
            ~PreAllocator() {}
    
            pointer address (reference value) const {return &value;}
            const_pointer address (const_reference value) const {return &value;}
    
            pointer allocate (size_type n, const void* hint = 0) {return memory_ptr;}
            void deallocate (T* ptr, size_type n) {}
    
            void construct (pointer ptr, const T& val) {new (ptr) T (val);}
    
            template
            void destroy (U* ptr) {ptr->~U();}
            void destroy (pointer ptr) {ptr->~T();}
    
            size_type max_size() const {return memory_size;}
    
            template
            struct rebind
            {
                typedef PreAllocator other;
            };
    };
    
    int main()
    {
        int my_arr[100] = {0};
        std::vector > my_vec(PreAllocator(&my_arr[0], 100));
        my_vec.push_back(1024);
        std::cout<<"My_Vec[0]: "< > my_heap_vec(PreAllocator(&my_heap_ptr[0], 100));
        my_heap_vec.push_back(1024);
        std::cout<<"My_Heap_Vec[0]: "<

    For C++11, you can use the following:

    #include 
    #include 
    #include 
    #include 
    
    template 
    class PreAllocator
    {
        private:
            T* memory_ptr;
            std::size_t memory_size;
    
        public:
            typedef std::size_t     size_type;
            typedef T*              pointer;
            typedef T               value_type;
    
            PreAllocator(T* memory_ptr, std::size_t memory_size) : memory_ptr(memory_ptr), memory_size(memory_size) {}
    
            PreAllocator(const PreAllocator& other) throw() : memory_ptr(other.memory_ptr), memory_size(other.memory_size) {};
    
            template
            PreAllocator(const PreAllocator& other) throw() : memory_ptr(other.memory_ptr), memory_size(other.memory_size) {};
    
            template
            PreAllocator& operator = (const PreAllocator& other) { return *this; }
            PreAllocator& operator = (const PreAllocator& other) { return *this; }
            ~PreAllocator() {}
    
    
            pointer allocate(size_type n, const void* hint = 0) {return memory_ptr;}
            void deallocate(T* ptr, size_type n) {}
    
            size_type max_size() const {return memory_size;}
    };
    
    int main()
    {
        int my_arr[100] = {0};
        std::vector> my_vec(0, PreAllocator(&my_arr[0], 100));
        my_vec.push_back(1024);
        std::cout<<"My_Vec[0]: "<> my_heap_vec(0, PreAllocator(&my_heap_ptr[0], 100));
        my_heap_vec.push_back(1024);
        std::cout<<"My_Heap_Vec[0]: "<

    Notice the difference between the two allocators! This will work with both heap buffers/arrays and stack buffer/arrays. It will also work with most containers. It is safer to use the Pre-C++11 version because it will be backwards compatible and work with more containers (ie: std::List).

    You can just place the allocator in a header and use it as much as you want in any projects. It is good if you want to use SharedMemory or any buffer that is already allocated.

    WARNING: DO NOT use the same buffer for multiple containers at the same time! A buffer can be reused but just make sure no two containers use it at the same time.

    Example:

    int my_arr[100] = {0};
    std::vector > my_vec(PreAllocator(&my_arr[0], 100));
    std::vector > my_vec2(PreAllocator(&my_arr[0], 100));
    
    my_vec.push_back(1024);
    my_vec2.push_back(2048);
    
    std::cout<<"My_Vec[0]: "<

    The output of the above is 2048! Why? Because the last vector overwrote the values of the first vector since they share the same buffer.

提交回复
热议问题