Django: ordering numerical value with order_by

Question

I\'m in a situation where I must output a quite large list of objects by a CharField used to store street addresses.

My problem is, that obviously the data is ordere

Answer 1

In case you need to sort version numbers consisting of multiple numbers separated by a dot (e.g. 1.9.0, 1.10.0), here is a postgres-only solution:

class VersionRecordManager(models.Manager):

    def get_queryset(self):
        return super().get_queryset().extra(
            select={
                'natural_version': "string_to_array(version, '.')::int[]",
            },
        )

    def available_versions(self):
        return self.filter(available=True).order_by('-natural_version')

    def last_stable(self):
        return self.available_versions().filter(stable=True).first()

class VersionRecord(models.Model):
    objects = VersionRecordManager()
    version = models.CharField(max_length=64, db_index=True)
    available = models.BooleanField(default=False, db_index=True)
    stable = models.BooleanField(default=False, db_index=True)

In case you want to allow non-numeric characters (e.g. 0.9.0 beta, 2.0.0 stable):

def get_queryset(self):
    return super().get_queryset().extra(
        select={
            'natural_version':
                "string_to_array(                     "  
                "   regexp_replace(                   "  # Remove everything except digits
                "       version, '[^\d\.]+', '', 'g'  "  # and dots, then split string into
                "   ), '.'                            "  # an array of integers.
                ")::int[]                             "
        }
    )