Compact way to assign values by slicing list in Python

Question

I have the following list

bar = [\'a\',\'b\',\'c\',\'x\',\'y\',\'z\']

What I want to do is to assign 1st, 4th and 5th values of bar

Answer 1

Yet another method:

from itertools import compress

bar = ['a','b','c','x','y','z']
v1, v2, v3 = compress(bar, (1, 0, 0, 1, 1, 0))

In addition, you can ignore length of the list and skip zeros at the end of selectors:

v1, v2, v3 = compress(bar, (1, 0, 0, 1, 1,))

https://docs.python.org/2/library/itertools.html#itertools.compress