How to deserialize JSON into flat, Map-like structure?

Question

Have in mind that the JSON structure is not known before hand i.e. it is completely arbitrary, we only know that it is JSON format.

For example,

The followin

Answer 1

You can achieve something like that using the Typesafe Config Library as in the following example:

import com.typesafe.config.*;
import java.util.Map;
public class TypesafeConfigExample {
  public static void main(String[] args) {
    Config cfg = ConfigFactory.parseString(
      "   \"Port\":\n" +
      "   {\n" +
      "       \"@alias\": \"defaultHttp\",\n" +
      "       \"Enabled\": \"true\",\n" +
      "       \"Number\": \"10092\",\n" +
      "       \"Protocol\": \"http\",\n" +
      "       \"KeepAliveTimeout\": \"20000\",\n" +
      "       \"ThreadPool\":\n" +
      "       {\n" +
      "           \"@enabled\": \"false\",\n" +
      "           \"Max\": \"150\",\n" +
      "           \"ThreadPriority\": \"5\"\n" +
      "       },\n" +
      "       \"ExtendedProperties\":\n" +
      "       {\n" +
      "           \"Property\":\n" +
      "           [                         \n" +
      "               {\n" +
      "                   \"@name\": \"connectionTimeout\",\n" +
      "                   \"$\": \"20000\"\n" +
      "               }\n" +
      "           ]\n" +
      "       }\n" +
      "   }\n" +
      "}");

    // each key has a similar form to what you need
    for (Map.Entry e : cfg.entrySet()) {
      System.out.println(e);
    }
  }
}