Removing character in list of strings

Question

If I have a list of strings such as:

[(\"aaaa8\"),(\"bb8\"),(\"ccc8\"),(\"ffffdffffd8\")...]

What should I do in order to get rid of all the

Answer 1

lst = [("aaaa8"),("bb8"),("ccc8"),("ffffdffffd8")...]

msg = filter(lambda x : x != "8", lst)

print msg

EDIT: For anyone who came across this post, just for understanding the above removes any elements from the list which are equal to 8.

Supposing we use the above example the first element ("aaaaa8") would not be equal to 8 and so it would be dropped.

To make this (kinda work?) with how the intent of the question was we could perform something similar to this

msg = filter(lambda x: x != "8", map(lambda y: list(y), lst))

• I am not in an interpreter at the moment so of course mileage may vary, we may have to index so we do list(y[0]) would be the only modification to the above for this explanation purposes.

What this does is split each element of list up into an array of characters so ("aaaa8") would become ["a", "a", "a", "a", "8"].

This would result in a data type that looks like this

msg = [["a", "a", "a", "a"], ["b", "b"]...]

So finally to wrap that up we would have to map it to bring them all back into the same type roughly

msg = list(map(lambda q: ''.join(q), filter(lambda x: x != "8", map(lambda y: list(y[0]), lst))))

I would absolutely not recommend it, but if you were really wanting to play with map and filter, that would be how I think you could do it with a single line.