How can I get the source code for the linux utility tail?

Question

this command is really very useful but where I can get the source code to see what is going on inside .

thanks .

Answer 1

/`*This example implements the option n of tail command.*/`

    #define _FILE_OFFSET_BITS 64
    #include 
    #include 
    #include 
    #include 
    #include 
    #include 

    #define BUFF_SIZE 4096

    FILE *openFile(const char *filePath)
    {
      FILE *file;
      file= fopen(filePath, "r");
      if(file == NULL)
      {
        fprintf(stderr,"Error opening file: %s\n",filePath);
        exit(errno);
      }
      return(file);
    }

    void printLine(FILE *file, off_t startline)
    {
      int fd;
      fd= fileno(file);
      int nread;
      char buffer[BUFF_SIZE];
      lseek(fd,(startline + 1),SEEK_SET);
      while((nread= read(fd,buffer,BUFF_SIZE)) > 0)
      {
        write(STDOUT_FILENO, buffer, nread);
      }
    }

    void walkFile(FILE *file, long nlines)
    {
      off_t fposition;
      fseek(file,0,SEEK_END);
      fposition= ftell(file);
      off_t index= fposition;
      off_t end= fposition;
      long countlines= 0;
      char cbyte;

      for(index; index >= 0; index --)
      {
        cbyte= fgetc(file);
        if (cbyte == '\n' && (end - index) > 1)
        {
          countlines ++;
          if(countlines == nlines)
          {
        break;
          }
         }
        fposition--;
        fseek(file,fposition,SEEK_SET);
      }
      printLine(file, fposition);
      fclose(file);
    }

    int main(int argc, char *argv[])
    {
      FILE *file;
      file= openFile(argv[2]);
      walkFile(file, atol(argv[1]));
      return 0;
    }

    /*Note: take in mind that i not wrote code to parse input options and arguments, neither code to check if the lines number argument is really a number.*/