Alternative for __dirname in node when using the --experimental-modules flag

Question

I use the flag --experimental-modules when running my node application in order to use ES6 modules.

However when I use this flag the metavariable

Answer 1

As Geoff pointed out the following code returns not the module's path but working directory.

import path from 'path';
const __dirname = path.resolve();

works with --experimental-modules