Given an array:
array = [[:a,:b],[:a,:c],[:c,:b]]
Return the following hash:
hash = { :a => [:b,:c
EDIT: In Ruby 2.1+, you can use Array#to_h
pry(main)> [[:a,:b],[:a,:c],[:c,:b]].to_h
=> {:a=>:c, :c=>:b}
END EDIT
The public [] method on the Hash class accepts a key-value pair array and returns a hash with the first element of the array as key and the second as value.
The last value in the key-value pair will be the actual value when there are key duplicates.
Hash[[[:a,:b],[:a,:c],[:c,:b]]]
=> {:a=>:c, :c=>:b}
This syntax is valid in 1.9.3+ ; I'm not sure about earlier Ruby versions (it's not valid in 1.8.7)
ref: http://www.ruby-doc.org/core-2.1.0/Hash.html#method-c-5B-5D
Another interesting way of doing it would be using the inject method: (obviously the method above is more succinct and recommended for this specific problem)
[ [:a, :b], [:a, :c], [:c, :b] ].inject({}) { |memo, obj|
memo[obj.first] = obj.last
memo
}
=> {:a=>:c, :c=>:b}
inject iterates over the enumerable, your array in this case, starting with the injected parameter, in this case the empty hash {}.
For each object in the enumerable, the block is called with the variables memo and obj:
obj is the current object in the array
memo is the value that has been returned by your block's last iteration (for the first iteration, it's what you inject)