Python: Get URL path sections

Question

How do I get specific path sections from a url? For example, I want a function which operates on this:

http://www.mydomain.com/hithere?image=2934
         


        

Answer 1

Note in Python3 import has changed to from urllib.parse import urlparse See documentation. Here is an example:

>>> from urllib.parse import urlparse
>>> url = 's3://bucket.test/my/file/directory'
>>> p = urlparse(url)
>>> p
ParseResult(scheme='s3', netloc='bucket.test', path='/my/file/directory', params='', query='', fragment='')
>>> p.scheme
's3'
>>> p.netloc
'bucket.test'
>>> p.path
'/my/file/directory'