Get ceiling integer from number in linux (BASH)

Question

How would I do something like:

ceiling(N/500)

N representing a number.

But in a linux Bash script

Answer 1

Without specifying any function, we can use the following awk script:

echo x y | awk '{ r=$1 % $2; q=$1/y; if (r != 0) q=int(q+1); print q}'

Not sure this one get any logical error or not. Please correct.