Get ceiling integer from number in linux (BASH)

Question

How would I do something like:

ceiling(N/500)

N representing a number.

But in a linux Bash script

Answer 1

This is a simple solution using Awk:

If you want the ceil of ($a/$b) use

echo "$a $b" | awk '{print int( ($1/$2) + 1 )}'

and the floor use

echo "$a $b" | awk '{print int($1/$2)}'

Note that I just echo the dividend '$a' as the first field of the line to awk and the divisor '$b' as the second.