Can the 'type' of a lambda expression be expressed?

Question

Thinking of lambda expressions as \'syntactic sugar\' for callable objects, can the unnamed underlying type be expressed?

An example:

struct gt {         


        

Answer 1

In Microsoft Visual Studio at least (I haven't tried this with other compilers), and if you don't capture anything, the type seems to be a regular function pointer:

std::string (*myFunctionPointer)(int x) = [] (int x) {
  char buffer[10];
  return std::string("Test ") + itoa(x, buffer, 10);
};
std::string testOutput = myFunctionPointer(123);