How to align pointer

Question

How do I align a pointer to a 16 byte boundary?

I found this code, not sure if its correct

char* p= malloc(1024);

if ((((unsigned long) p) % 16) !=          


        

Answer 1

In glibc library malloc, realloc always returns 8 bytes aligned. If you want to allocate memory with some alignment which is a higher power 2 then you can use memalign and posix_memalign. Read http://www.gnu.org/s/hello/manual/libc/Aligned-Memory-Blocks.html