Finding node order in XML document in SQL Server

Question

How can I find the order of nodes in an XML document?

What I have is a document like this:

Answer 1

You can get the position of the xml returned by a x.nodes() function like so:

row_number() over (order by (select 0))

For example:

DECLARE @x XML
SET @x = 'abc1def1abc2def2'

SELECT
    b.query('.'),
    row_number() over (partition by 0 order by (select 0))
FROM
    @x.nodes('/a/b') x(b)