[removed] Overriding XMLHttpRequest.open()

Question

How would I be able to override the XMLHttpRequest.open() method and then catch and alter it\'s arguments?

I\'ve already tried the proxy method but it d

Answer 1

You are not modifying the open method inherited by XMLHttpRequest objects but just adding a method to the XMLHttpRequest constructor which is actually never used.

I tried this code in facebook and I was able to catch the requests:

(function() {
    var proxied = window.XMLHttpRequest.prototype.open;
    window.XMLHttpRequest.prototype.open = function() {
        console.log( arguments );
        return proxied.apply(this, [].slice.call(arguments));
    };
})();

/*
    ["POST", "/ajax/chat/buddy_list.php?__a=1", true]
    ["POST", "/ajax/apps/usage_update.php?__a=1", true]
    ["POST", "/ajax/chat/buddy_list.php?__a=1", true]
    ["POST", "/ajax/canvas_ticker.php?__a=1", true]
    ["POST", "/ajax/canvas_ticker.php?__a=1", true]
    ["POST", "/ajax/chat/buddy_list.php?__a=1", true]
*/

So yeah the open method needs to be added to XMLHttpRequest prototype (window.XMLHttpRequest.prototype) not XMLHttpRequest constructor (window.XMLHttpRequest)