how to merge two sorted integer array in place using O(n) time and O(1) space cost

Question

For example, given an integer array and its two consecutive sequence \'s beginning position which are \'b1\' and \'b2\', furthermore provided with the position \'last\' whic

Answer 1

I had an interview (with a very important company) a couple of hours ago and I was asked that. There is the answer in Java

public static void main(String[] args) {
    int A[] = { 1, 3, 5, 6, 9 };
    int B[] = new int[12];
    B[0] = 3;
    B[1] = 6;
    B[2] = 8;
    B[3] = 10;
    B[4] = 11;
    B[5] = 13;
    B[6] = 15;
    mergeInB(A, B, 7);
    for (int n : B)
        System.out.print(n + " ");
}



 /**
 * @param a
 * @param b - it will be modified
 * @param j = length of b
 */
public static void mergeInB(int[] a, int[] b, int j) {
    int i = a.length - 1, k;
    j --;
    for (k = b.length-1; k >= 0; k--) {
         if (i >= 0 && j >= 0) {
             if (a[i] > b[j]) {
                 b[k] = a[i];
                 i --;
             }
             else 
              {
                 b[k] = b[j];
                 j --;
             }               
         }
         else break;
    }

    while(i>=0 && k >=0) {
         b[k] = a[i];
         k --;
         i --;
    }

    while(j>= 0 && k >=0) {
         b[k] = b[j];
         j--;
         k--;
     }
}