Python: try statement in a single line

Question

Is there a way in python to turn a try/except into a single line?

something like...

b = \'some variable\'
a = c | b #try statement goes here
<         


        

Answer 1

if you need to actually manage exceptions:
(modified from poke53280's answer)

>>> def try_or(fn, exceptions: dict = {}):
    try:
        return fn()
    except Exception as ei:
        for e in ei.__class__.__mro__[:-1]:
            if e in exceptions: return exceptions[e]()
        else:
            raise


>>> def context():
    return 1 + None

>>> try_or( context, {TypeError: lambda: print('TypeError exception')} )
TypeError exception
>>> 

note that if the exception is not supported, it will raise as expected:

>>> try_or( context, {ValueError: lambda: print('ValueError exception')} )
Traceback (most recent call last):
  File "", line 1, in 
    try_or( context, {ValueError: lambda: print('ValueError exception')} )
  File "", line 3, in try_or
    return fn()
  File "", line 2, in context
    return 1 + None
TypeError: unsupported operand type(s) for +: 'int' and 'NoneType'
>>> 

also if Exception is given, it will match anything below.
(BaseException is higher, so it will not match)

>>> try_or( context, {Exception: lambda: print('exception')} )
exception